18x^2-36x-32=0

Solution for 18x^2-36x-32=0 equation:

18x^2-36x-32=0

a = 18; b = -36; c = -32;
Δ = b2-4ac
Δ = -362-4·18·(-32)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-60}{2*18}=\frac{-24}{36}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+60}{2*18}=\frac{96}{36}
=2+2/3
$